5v^2+7v-3=-v2

Solution for 5v^2+7v-3=-v2 equation:

5v^2+7v-3=-v2

We move all terms to the left:

5v^2+7v-3-(-v2)=0

We add all the numbers together, and all the variables

5v^2-(-1v^2)+7v-3=0

We get rid of parentheses

5v^2+1v^2+7v-3=0

We add all the numbers together, and all the variables

6v^2+7v-3=0

a = 6; b = 7; c = -3;
Δ = b2-4ac
Δ = 72-4·6·(-3)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-11}{2*6}=\frac{-18}{12}
=-1+1/2
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+11}{2*6}=\frac{4}{12}
=1/3
$